[Shootout-list] What people say about shootout (correct answers)

[Bengt Kleberg]

Sebastien Loisel wrote:
>>however, i still think that the observable result for a shootout
>>benchmark should be the same for all languages. ie,
>>
>>        | A - C | < epsilon
> 
> 
> I wanted to do this at first but you can achieve the same effect by
> truncating the output, if you're lucky. But you can cook up your own

i think this means that you agree that it is a good thing to keep the 
observable result for a shootout benchmark the same for all languages.
how this should be achived is sometimes a difficult question, and better 
solved on a benchmark by benchmark basis, imho.


bengt