[Bash-completion-devel] Weirdness when invoking php in a completion function

[David Paleino]

On Mon, 02 May 2011 21:10:29 +0300, Ville Skyttä wrote:

> $ bash --norc
> $ _php() { COMPREPLY=( $( compgen -W '$( php -h )' -- "$2" ) ); }
> $ complete -F _php php
> 
> Then, tried completing "php -<TAB>".  All good so far, stuff starting
> with - is listed.  But then hit another tab and things go south: no more
> completing, hitting tab actually inserts a tab to the console.  The php
> invocation doesn't even have to be related to creating the completions,
> for example this function shows the same behavior:
> 
> _php() {
>      php -h &>/dev/null
>      COMPREPLY=( $( compgen -W '--foo --bar' -- "$2" ) )
> }
> 
> I've never seen this behavior before, and it seems to happen only with
> php for me.  And my own system is the only one I see this with:
> 
> bash 4.1.7(1)-release, PHP 5.3.6 (Fedora 14)
> Ditto with bash 3.2.39(1)-release on the same box.
> 
> I cannot reproduce the problem with the following, it works fine with them:
> 
> [..]
> bash 4.1.5(1)-release, php 5.3.3-7+squeeze1 (Debian)

Neither do I :/
(with php 5.3.6-10 and the same Bash as yours on Debian)

> Anyone have ideas what might cause this?

What does bash say after a set -x? Anything useful?

Cluelessly,
David

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